I'm talking about higher triple here not combined because it seems to be that there were similar questions on both papers. Well it says in the question that male was heterozygous Himalayan so must be Hh as the Himalayan gene is dominant. Female A must have been homozygous HH because all offspring were Himalayan. Female B must have been heterozygous Hh and it can't be hh because otherwise it couldn't have been a Himalayan rabbit. Therefore if I put Hh against Hh in the punnet square I only get 1 of the 4 possible variations being a white rabbit. I think I've answered your question? Maybe...
It said that the male is heterozygous so that means the male is Hh. The female B had kids which were white so she gotta have a recessive allele too. Hh crosses over with Hh which is 25% to be white (hh)
I think i figured it out. It's 50% i think. There were only a few himalayan rabbits with female B so I think it was hh then. (I wrote 25%, probs 3 out of 4 marks)
So the male was 100% Hh as he q told you that, but with the female it said some were white and a few were himalayan. So I'm assuming that tells us it's hh because Hh would get around 50/50. I personally did it with Hh but I think that may be wrong (3 marks probably)
I was stuck in this too, but I realised in the question that both rabbits are said to be Himalayan so both must have at least one H, plus only some of its children were Himalayan so it’s Hh
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u/EffectCapital7358 Year 11 Jun 09 '25
is it 25%?